VBA/Excel/Access/Word/Date Functions/Dynamic Array
Версия от 16:33, 26 мая 2010; (обсуждение)
Содержание
- 1 A destroying the old values by using the Preserve keyword
- 2 Declaring and Working with Dynamic Arrays
- 3 Dynamic Arrays
- 4 There"s a potential problem when you try to resize the array:
- 5 Transpose() sub procedure is using a dynamic array that is re-dimensioned with two dimensions.
- 6 Use ReDim to create dynamic array
- 7 Use the Preserve keyword to keep the values
- 8 Using a Dynamic Array
A destroying the old values by using the Preserve keyword
Sub redimDemo()
Dim MyArray() As Integer
ReDim MyArray(12)
ReDim Preserve MyArray(12)
End Sub
Declaring and Working with Dynamic Arrays
Sub DynamicArray()
Dim astrNames() As String
Dim intCounter As Integer
Dim vntAny As Variant
"Resize the array to hold two elements
ReDim astrNames(1)
astrNames(0) = "A"
astrNames(1) = "B"
"Use a For...Each loop to loop through the
"elements of the array
For Each vntAny In astrNames
Debug.Print vntAny
Next vntAny
End Sub
Dynamic Arrays
Sub arrayTest1()
Dim i As Integer
Dim intMyScores() As Integer
Dim intArraySize As Integer
intArraySize = 10
ReDim intMyScores(intArraySize)
For i = 1 To intArraySize
intMyScores(i) = i
Next
For i = 0 To intArraySize
Debug.Print "For array element " & i & " the number is " & intMyScores(i)
Next
End Sub
There"s a potential problem when you try to resize the array:
Sub ResizeDynamic()
Dim astrNames() As String
Dim intCounter As Integer
Dim vntAny As Variant
"Resize the array to hold two elements
ReDim astrNames(1)
astrNames(0) = "A"
astrNames(1) = "B"
"Resize the array to hold four elements
ReDim astrNames(3)
"Populate the last two elements
astrNames(2) = "C"
astrNames(3) = "D"
For Each vntAny In astrNames
Debug.Print vntAny
Next vntAny
End Sub
Transpose() sub procedure is using a dynamic array that is re-dimensioned with two dimensions.
Public Sub DynamicTranspose()
Dim I As Integer
Dim J As Integer
Dim transArray() As Integer
Dim numRows As Integer
Dim numColumns As Integer
Do
numRows = I
I = I + 1
Loop Until Cells(I, "A").Value = ""
I = 0
Do
numColumns = I
I = I + 1
Loop Until Cells(1, Chr(I + 64)).Value = ""
ReDim transArray(numRows - 1, numColumns - 1)
"
For I = 1 To numColumns
For J = 1 To numRows
transArray(J - 1, I - 1) = Cells(J, Chr(I + 64)).Value
Next J
Next I
"
Range("A1:C10").ClearContents
"
For I = 1 To numColumns
For J = 1 To numRows
Cells(I, Chr(J + 64)).Value = transArray(J - 1, I - 1)
Next J
Next I
End Sub
Use ReDim to create dynamic array
Sub arrayTest3()
Dim i As Integer
Dim intMyScores() As Integer
Dim intArraySize As Integer
intArraySize = 10
ReDim intMyScores(1 To intArraySize)
For i = 1 To intArraySize
intMyScores(i) = i
Next
For i = 1 To intArraySize
Debug.Print "For array element " & i & " the number is " & intMyScores(i)
Next
End Sub
Use the Preserve keyword to keep the values
Sub ResizePreserve()
Dim astrNames() As String
Dim intCounter As Integer
Dim vntAny As Variant
ReDim astrNames(1)
astrNames(0) = "A"
astrNames(1) = "B"
ReDim Preserve astrNames(3)
astrNames(2) = "C"
astrNames(3) = "D"
For Each vntAny In astrNames
Debug.Print vntAny
Next vntAny
End Sub
Using a Dynamic Array
Sub DynArray()
Dim counter As Integer
Dim myArray() As Integer
ReDim myArray(5)
Dim myValues As String
For counter = 1 To 5
myArray(counter) = counter + 1
myValues = myValues & myArray(counter) & Chr(13)
Next
ReDim Preserve myArray(10)
For counter = 6 To 10
myArray(counter) = counter * 8
myValues = myValues & myArray(counter) & Chr(13)
Next counter
Debug.Print myValues
For counter = 1 To 10
Debug.Print myArray(counter)
Next counter
End Sub