VB.Net/XML LINQ/XPath — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
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(нет различий)
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Текущая версия на 12:45, 26 мая 2010
Loop through the query results and display the information to the screen.
Imports System
Imports System.Xml.Linq
Imports System.Xml.XPath
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("EmployeesAndTasks.xml")
Dim xpathQuery = employees.XPathSelectElements("/Employee/Tasks/Task")
For Each task In xpathQuery
Console.WriteLine("{0,-15} - {1} ({2})", task.Parent.Parent.<Name>.Value, task.<Name>.Value, task.<Description>.Value)
Next
End Sub
End Class
Selecting node by XPath
Public Class MainClass
Shared Sub Main()
Dim file As String = "books.xml"
Dim doc As New System.Xml.XmlDocument
doc.Load(file)
Dim nodes As System.Xml.XmlNodeList
nodes = doc.SelectNodes("shelf/book")
Dim counter = 0
Do Until counter = nodes.Count
System.Console.WriteLine(nodes.Item(counter).SelectSingleNode("title").InnerText & " by " & nodes.Item(counter).SelectSingleNode("author").InnerText & vbCrLf)
counter = counter + 1
Loop
End Sub
End Class
Use XPath to get the tasks for each employee.
Imports System
Imports System.Xml.Linq
Imports System.Xml.XPath
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("EmployeesAndTasks.xml")
"
Dim xpathQuery = employees.XPathSelectElements("/Employee/Tasks/Task")
End Sub
End Class