VB.Net/XML LINQ/Query — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
Admin (обсуждение | вклад) м (1 версия) |
(нет различий)
|
Текущая версия на 12:45, 26 мая 2010
Содержание
- 1 Build an element with a query
- 2 Build a query to join the two XML trees on the employee"s Id.
- 3 Creating new Xml element in the query
- 4 Display the employee names and their hourly rate
- 5 Display the employee names and their new hourly rate.
- 6 Execute the query and loop through the results, displaying the Information to the screen.
- 7 Loop through all of the Employee elements and remove the HireDate element.
- 8 Loop through all the Employee nodes and insert the new "TerminationDate" node and the "Status" attribute
- 9 Loop through all the HourlyRate elements, setting them to the new payrate, which is the old rate * 5%.
- 10 Loop through a node in Xml document
- 11 Query for all of the employees that make (HourlyRate) more than $100 an hour
- 12 Query the XML Tree and get the Name and Hourly Rate elements.
- 13 Query Xml document by Node value
- 14 Use LINQ to get the tasks for each employee and order them by the employee"s name.
- 15 Using For Each to loop through the result of Xml query
Build an element with a query
Imports System.Collections.Generic
Class Car
Public PetName As String
Public ID As Integer
End Class
Module Program
Sub Main()
Dim data As New List(Of Car)
data.Add(New Car With {.PetName = "A", .ID = 10})
data.Add(New Car With {.PetName = "Pat", .ID = 11})
data.Add(New Car With {.PetName = "Danny", .ID = 12})
data.Add(New Car With {.PetName = "B", .ID = 13})
Dim vehicles As XElement = _
<Inventory>
<%= From c In data _
Select <Car ID=<%= c.ID %>>
<PetName><%= c.PetName %></PetName>
</Car> %>
</Inventory>
Console.WriteLine(vehicles)
End Sub
End Module
Build a query to join the two XML trees on the employee"s Id.
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim titles As XElement = XElement.Load("Titles.xml")
Dim query = From emp In employees.<Employee> _
Group Join title In titles.<Title> _
On emp.@id Equals title.@empId _
Into TitleList = Group _
Select EmployeeName = emp.<Name>.Value, _
TitleList
For Each emp In query
Console.WriteLine(emp.EmployeeName)
For Each title In emp.TitleList
Console.WriteLine("{0} - {1}", title.<Name>.Value, title.<Status>.Value)
Next
Next
End Sub
End Class
Creating new Xml element in the query
Imports System
Imports System.Reflection
Imports System.Xml
Module Module1
Sub Main()
Dim xml As XElement = XElement.Load("People.xml")
Dim query = From p In xml.Descendants("person"), s In xml.Descendants("id") _
Where p.Element("id").Value = s.Attribute("id").Value _
Select New With {.FirstName = p.Element("firstname").Value, _
.LastName = p.Element("lastname").Value, _
.Amount = s.Attribute("salar").Value}
For Each record In query
Console.WriteLine("Person: {0} {1}, Salary {2}", record.FirstName, _
record.LastName, _
record.Amount)
Next
End Sub
End Module
Display the employee names and their hourly rate
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim beforeQuery = From ele In employees.<Employee> Select Name = ele.<Name>.Value, Wage = CDbl(ele.<HourlyRate>.Value)
For Each ele In beforeQuery
Console.WriteLine("{0} gets paid ${1} an hour.", ele.Name, ele.Wage.ToString())
Next
End Sub
End Class
Display the employee names and their new hourly rate.
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim afterQuery = From ele In employees.<Employee> Select Name = ele.<Name>.Value, Wage = CDbl(ele.<HourlyRate>.Value)
For Each ele In afterQuery
Console.WriteLine("{0} gets paid ${1} an hour.", ele.Name, ele.Wage.ToString("##.##"))
Next
End Sub
End Class
Execute the query and loop through the results, displaying the Information to the screen.
Imports System
Imports System.Xml.Linq
Imports System.Xml.XPath
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("EmployeesAndTasks.xml")
Dim linqQuery = From task In employees.<Employee>...<Task> _
Select EmployeeName = task.Parent.Parent.<Name>.Value, _
TaskName = task.<Name>.Value, _
task.<Description>.Value _
Order By EmployeeName
For Each task In linqQuery
Console.WriteLine("{0,-15} - {1} ({2})", task.EmployeeName, task.TaskName, task.Description)
Next
End Sub
End Class
Loop through all of the Employee elements and remove the HireDate element.
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
employees.<Employee>.ElementAt(3).Remove()
For Each ele In employees.<Employee>.ToList
ele.SetElementValue("HireDate", Nothing)
Next
Console.WriteLine(employees.ToString)
End Sub
End Class
Loop through all the Employee nodes and insert the new "TerminationDate" node and the "Status" attribute
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim newEmployee = <Employee id=<%= 1 %>>
<Name>First</Name>
<Title>Coder</Title>
<HireDate>07/15/2006</HireDate>
<HourlyRate>9.95</HourlyRate>
</Employee>
employees.Add(newEmployee)
For Each ele In employees.<Employee>
ele.Add(<TerminationDate></TerminationDate>)
ele.Add(New XAttribute("Status", ""))
Next
Console.WriteLine(employees.ToString())
End Sub
End Class
Loop through all the HourlyRate elements, setting them to the new payrate, which is the old rate * 5%.
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim beforeQuery = From ele In employees.<Employee> Select Name = ele.<Name>.Value, Wage = CDbl(ele.<HourlyRate>.Value)
Dim currentPayRate As Double = 0
For Each ele In employees.<Employee>.<HourlyRate>
currentPayRate = (ele.Value) + ((ele.Value) * 0.05)
ele.SetValue(currentPayRate)
Next
End Sub
End Class
Loop through a node in Xml document
Module Program
Sub Main()
Dim doc As XElement = XElement.Load("Inventory.xml")
Dim petNames = From pn In doc...<PetName> Select pn.Value
For Each name In petNames
Console.WriteLine("Name: {0}", name)
Next
End Sub
End Module
Query for all of the employees that make (HourlyRate) more than $100 an hour
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim query = From ele In employees.<Employee> _
Where CDbl(ele.<HourlyRate>.Value) >= 100 _
Select ele.@id, ele.<Name>.Value, Pay = CDbl(ele.<HourlyRate>.Value) _
Order By Name
For Each emp In query
Console.WriteLine("[{0,-2}] {1,-25} ${2,-6}", emp.id, emp.Name, emp.Pay.ToString("##.00"))
Next
End Sub
End Class
Query the XML Tree and get the Name and Hourly Rate elements.
Imports System
Imports System.Xml.Linq
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("Employees.xml")
Dim afterQuery = From ele In employees.<Employee> Select Name = ele.<Name>.Value, Wage = CDbl(ele.<HourlyRate>.Value)
End Sub
End Class
Query Xml document by Node value
Module Program
Sub Main()
Dim doc As XElement = XElement.Load("Inventory.xml")
Dim fords = From c In doc...<Make> Where c.Value = "Ford" Select c
For Each f In fords
Console.WriteLine("Make: {0}", f)
Next
End Sub
End Module
Use LINQ to get the tasks for each employee and order them by the employee"s name.
Imports System
Imports System.Xml.Linq
Imports System.Xml.XPath
Public Class MainClass
Public Shared Sub Main()
Dim employees As XElement = XElement.Load("EmployeesAndTasks.xml")
Dim linqQuery = From task In employees.<Employee>...<Task> _
Select EmployeeName = task.Parent.Parent.<Name>.Value, _
TaskName = task.<Name>.Value, _
task.<Description>.Value _
Order By EmployeeName
End Sub
End Class
Using For Each to loop through the result of Xml query
Imports System
Imports System.Reflection
Imports System.Xml
Module Module1
Sub Main()
Dim xml As XElement = XElement.Load("People.xml")
Dim query = From s In xml.Elements("salary").Elements("id") _
Where s.Attribute("year").Value = 2004 _
Select s
For Each record In query
Console.WriteLine("Amount: {0}", record.Attribute("salaryyear"))
Next
End Sub
End Module